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Data Interpretation


( 1 ) A sum is invested at compounded interest payable annually. The interest in the first two successive years was Rs. 400 and Rs. 420. The sum is
 1) Rs. 8000
 2) Rs.7500
 3) Rs. 8500
 4) Rs. 8200

Show Answer Report Discussion in forumAnswer : 1) Rs. 8000
Solution : simple Interest on Rs.400 for 1 year = 420  400 = 20
Rate = 100 * SI/PT = 100 * 20/(400 * 1) = 5%
Rs.400 is the interest on the sum for 1st year
Hence, sum = 100 * SI/RT = 100 * 400/5 * 1 = Rs. 8000
discussion
Answer : 1) Rs. 8000



( 2 ) Rs.100 doubled in 5 years when compounded annually. How many more years will it take to get another Rs.200 compound interest
 1) 3years
 2) 5years
 3) 6years
 4) 7years

Show Answer Report Discussion in forumAnswer : 2) 5years
Solution : Rs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.
discussion
Answer : 2) 5years



( 3 ) Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
 1) Rs.81000
 2) Rs.80000
 3) Rs.75000
 4) Rs.64000

Show Answer Report Discussion in forumAnswer : 1) Rs.81000
Solution : 64000 * (9/8) * (9/8) = 81000
discussion
Answer : 1) Rs.81000



( 4 ) Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
 1) Rs.1261
 2) Rs.9261
 3) Rs.9621
 4) Rs.9162

Show Answer Report Discussion in forumAnswer : 2) Rs.9261
Solution : A = 8000(21/20)^{3} = 9261
discussion
Answer : 2) Rs.9261



( 5 ) A $1000 face value Series S50 compound interest Canada Savings Bond (CSB) was presented to a credit union branch for redemption.What amount did the owner receive if the redemption was requested on:January 17, 2001?
 1) 1206
 2) 1306
 3) 1406
 4) 1506

Show Answer Report Discussion in forumAnswer : 2) 1306
Solution : I= ptr
Therefore, the total amount the owner received on January 17, 2001 was $1295.57 + $10.47 = $1306.04
discussion
Answer : 2) 1306



( 6 ) In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?
 1) 1years
 2) 2years
 3) 3years
 4) 4years

Show Answer Report Discussion in forumAnswer : 3) 3years
Solution : Principal = Rs. 1000
Amount = Rs. 1331
Rate = 10% p.a.
Let the time be n years. Then,
[ 1000 (1+ (10/100))^{n}] = 1331
or (11/10)^{n} = (1331/1000) = (11/10)^{3}
n = 3 years
discussion
Answer : 3) 3years



( 7 ) A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
 1) Rs.25600.24
 2) Rs.32000.50
 3) Rs.18060.36
 4) Rs.18600

Show Answer Report Discussion in forumAnswer : 1) Rs.25600.24
Solution : 6 1/4% = 1/16
x * (15/16) * (15/16) * (15/16) = 21093
x = 25600.24
discussion
Answer : 1) Rs.25600.24



( 8 ) Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years?
 1) Rs.420
 2) Rs.400
 3) Rs.375
 4) Rs.380

Show Answer Report Discussion in forumAnswer : 2) Rs.400
Solution : 441 = P(21/20)^{2}
P = 400
discussion
Answer : 2) Rs.400



( 9 ) A construction company borrowed Rs. 8,50,000 for 5 years at interest rate 1 ½ % p.a. How much annual interest, the company had to pay?
 1) Rs.63,750
 2) Rs. 1,27,500
 3) Rs.12,750
 4) Rs.25,000

Show Answer Report Discussion in forumAnswer : 1) Rs.63,750
Solution : S.I = 850000 * (3/2) *100 = 4250 * 15 = Rs. 63750
discussion
Answer : 1) Rs.63,750



( 10 ) The population of a town is 50,000. It decreases by 20 per thousand per year. Find out the population after 2 years?
 1) Rs. 46,000
 2) Rs. 46,020
 3) Rs. 48,000
 4) Rs. 48,020

Show Answer Report Discussion in forumAnswer : 4) Rs. 48,020
Solution : Required population = Initial population (1  r/1000)^{n}
= 50,000 (1  20/1000)^{2}
= 48,020
discussion
Answer : 4) Rs. 48,020
