#### Data Interpretation

• ( 1 ) If the cost of k metres of cable wire is c rupees, then what is the cost of m metres of cable wire at the same rate?

• 1) Rs. (mc)
• 2) Rs. (mc/k)
• 3) Rs. (kc)
• 4) Rs. (km/c)
• Discussion in forum
Solution : Cost of k metres = Rs. C
Cost of 1 metre = Rs.(c/k)
Cost of m metres = Rs.[(c/k).m] = Rs.(mc/k)

discussion

• ( 2 ) If 8 goldsmiths, working 9 hours a day, can make 20 ornaments in 24 days, how many ornaments will 18 goldsmiths make in 36 days, each working 8 hours a day?

• 1) 126
• 2) 60
• 3) 92
• 4) 138
• Discussion in forum
Solution :
$\begin{array}{}\text{Goldsmiths 8 : 18}\text{His/Day 9 : 8}\text{Days 24 : 36}\end{array}}$ : : 20 : x
=> 8 * 9 * 24 * x = 18 * 8 * 36 * 20
=> or x = 60

discussion

• ( 3 ) Running at the same constant rate, 6 identical machines can produce a total of 270 pens per minute. At this rate, how many pens could 10 such machines produce in 4 minutes?

• 1) 1500
• 2) 1545.6
• 3) 1640.33
• 4) 1800
• Discussion in forum
Solution : Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
$\begin{array}{}\text{Machines 6 : 10}\text{Time(in minutes) 1 : 4}\end{array}}$ :: 270 : x
=> 6 * 1 * x = 10 * 4 * 270
=> x = (10 * 4 *270)/6
=> x = 1800

discussion

• ( 4 ) If 17 labours can dig a ditch 20 m long in 18 days, working 8 hours a day; how many more labours should be engaged to dig a similar ditch 39 m long in 6 days, ech labours working 9 hours a day?

• 1) 34
• 2) 51
• 3) 68
• 4) 85
• Discussion in forum
Solution : Let the total number of men to be engaged be x.
More length, More labours (Direct Proportion)
Less days, More labours (Indirect Proportion)
More hours per day, Less labours (Indirect Proportion)
$\begin{array}{}\text{Length 26 : 39}\text{Days 6 : 18}\text{Hours per day 9 : 8}\end{array}}$ :: 17 : x
=> (26 * 6 * 9 * x) = (39 * 18 * 8 * 17)
=> x = (39 * 18 * 8 * 17)/(26 * 6 * 9)
=> x = 68
Number of more labours = (68 - 17) = 51

discussion

• ( 5 ) A wheel rotates 10 times every minute and moves 20 cm during each rotation. How many ems does the wheel move in 1 hour?

• 1) 20000
• 2) 14000
• 3) 23000
• 4) 12000
• Discussion in forum
Solution : Number of wheel moves in 1 hour = 10 * 60 = 600
distance moved = 600 * 200 = 12000

discussion

• ( 6 ) 10 boys, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 boys work to complete the same work in 12 days?

• 1) 6
• 2) 10
• 3) 12
• 4) 15
• Discussion in forum
Solution : Let the required number of hours per day be x.
More boys, Less hours per day (Indirect Proportion)
Less days, more hours per day (Indirect Proportion)
$\begin{array}{}\text{Boys 15 : 10}\text{Days 12 : 18}\end{array}}$ :: 6 : x
=> 15 * 12 * x = 10 * 18 * 6
=> x = (10 * 18 * 6)/ (15 * 12)
=> x = 6

discussion

• ( 7 ) If forty lamps can be lighted 5 hours per day for 10 days for Rs. 21.25,then the number of lamps which can be lighted 4 hours daily for 30 days for Rs. 76.50, is :

• 1) 100
• 2) 50
• 3) 60
• 4) 150
• Discussion in forum
Solution :
$\begin{array}{}\text{Hrs/Day 4 : 5}\text{Money 21.25 : 76.50}\text{Days 30 : 10}\end{array}}$ : : 40 : x
4 * 21.25 * 30 * x = 5 * 76.50 * 10 * 40
so x = 60

discussion

• ( 8 ) A current pole 12 m high casts a shadow of length 18 m. The height of the tower, which casts a shadow of length 30 m under similar conditions will be:

• 1) 10 m
• 2) 20 m
• 3) 17.6 m
• 4) 21.25 m
• Discussion in forum
Solution : Let the height of the tower x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
18 : 30 :: 12 : x
18 * x = 12 * 30
x = 12 * 30/18
x = 20

discussion

• ( 9 ) If 10 men can crop a field in 8 days, then 8 men will crop the same field in :

• 1) 5 days
• 2) 4 days
• 3) 20 days
• 4) 10 days
• Discussion in forum
Solution : 8 : 10 :: 8 : x or 8x = 10 * 8
or x = 10.
Required number of days 10.

discussion

• ( 10 ) If p men, working p hours per day, can do p units of work in p days, then q men, working q hoyrs per day would be able to complete how many units of work in q days ?

• 1) p2/q3
• 2) p3/q2
• 3) q2/p3
• 4) q3/p2
• Discussion in forum
Solution : Let the required number of units of work be x.
More men, more work (Direct Proportion)
more working hours, more work (Direct Proportion)
more days, more work (Direct Proportion)
$\begin{array}{}\text{Men p : q}\text{Hours per day p : q}\text{Days p : q}\end{array}}$ : : p : x
∴ (p * p * p * x) = (q * q * q * p)
=> x = q3/p2.

discussion