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( 1 ) The maximum gap between two successive leap year is?
 1) 1
 2) 2
 3) 4
 4) 8

Show Answer Report Discussion in forumAnswer : 4) 8
Solution : This can be illustrated with an example.
Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
discussion
Answer : 4) 8



( 2 ) What was the day on 31^{st} Dec,2011 ?
 1) Monday
 2) Saturday
 3) Friday
 4) Sunday

Show Answer Report Discussion in forumAnswer : 2) Saturday
Solution : 31^{st} Dec, 2011 = (2010 years + Period from 1.1.2011 to 31.12.2011)
Odd days in 2000 years = 0
10 years has 2 leap years + 8 ordinary years.
Number of odd days in 10 years ( 2 * 2 + 8) = 5 odd days.
31^{st},Dec => complete year of 2011 (nonleap year) = 1 odd day.
Total number of odd days = (0 + 5 + 1) = 6.Given day is saturday.
discussion
Answer : 2) Saturday



( 3 ) January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
 1) Monday
 2) Sunday
 3) Tuesday
 4) Wednesday

Show Answer Report Discussion in forumAnswer : 3) Tuesday
Solution : The year 2007 is an ordinary year.
So, it has 1 odd day.
1^{st} day of the year 2007 was Monday.
1^{st} day of the year 2008 will be 1 day beyond Monday Hence, It will be Tuesday.
discussion
Answer : 3) Tuesday



( 4 ) The calendar of the year 2024 can be used again in the year?
 1) 2030
 2) 2052
 3) 2036
 4) 2048

Show Answer Report Discussion in forumAnswer : 2) 2052
Solution : Given year 2024 when divided by 4, leaves a remainder 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 2024 + 28 = 2052 .
discussion
Answer : 2) 2052



( 5 ) If July 9^{th},2013 falls on Sunday then Jan 7^{th},2014 falls on which day?
 1) Monday
 2) Sunday
 3) Wednesday
 4) Friday

Show Answer Report Discussion in forumAnswer : 2) Sunday
Solution : 1^{st},we count the number of odd days for the left over days in the given period.
Here,given period is 9.7.2013 to 7.1.2014
July Aug Sept Oct Nov Dec Jan
22 31 30 31 30 31 7 (left days)
1+ 3 + 2 + 3 + 2 + 3 + 0 (odd days) = 0 odd day
So,given day Sunday + 0 = Sunday is the required result.
discussion
Answer : 2) Sunday



( 6 ) If 25^{th} of August in a year is Thursday, the number of Mondays in that month is
 1) 4
 2) 5
 3) 3
 4) 2

Show Answer Report Discussion in forumAnswer : 2) 5
Solution : Given that 25^{th} August = Thursday
Hence 29^{th} August = Monday
So 22^{nd},15^{th} and 8^{th} and 1^{st} of August also will be Mondays
Number of Mondays in August = 5.
discussion
Answer : 2) 5



( 7 ) 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91?
 1) 20.12.91
 2) 22.12.91
 3) 24.12.91
 4) 25.12.91

Show Answer Report Discussion in forumAnswer : 3) 24.12.91
Solution : Given that 1.12.91 is the first Sunday
Hence we can assume that 3.12.91 is the 1^{st} Tuesday
If we add 7 days to 3.12.91, we will get 2^{nd} Tuesday
If we add 14 days to 3.12.91, we will get 3^{rd} Tuesday
If we add 21 days to 3.12.91, we will get 4^{th} Tuesday
=> 4^{th} Tuesday = (3.12.91 + 21 days) = 24.12.91.
discussion
Answer : 3) 24.12.91



( 8 ) If 1^{st} October is Sunday, then 1^{st} November will be
 1) Saturday
 2) Thursday
 3) Wednesday
 4) Tuesday

Show Answer Report Discussion in forumAnswer : 3) Wednesday
Solution : Given that 1^{st} October is Sunday
Number of days in October = 31.
31 days = 3 odd days(As we can reduce multiples of 7 from odd days which will not change anything)
Hence 1^{st} November = (Sunday + 3 odd days) = Wednesday
discussion
Answer : 3) Wednesday



( 9 ) Find the number of odd days in 425 days
 1) 3
 2) 4
 3) 5
 4) 6

Show Answer Report Discussion in forumAnswer : 1) 3
Solution : In 425 days there will be 3 odd days.
discussion
Answer : 1) 3



( 10 ) What was the day on 1^{st} January, 1 A.D.?
 1) Monday
 2) Tuesday
 3) Wednesday
 4) Sunday

Show Answer Report Discussion in forumAnswer : 1) Monday
Solution : On 1^{st} january, 1^{st} A.D. there will be Monday.
discussion
Answer : 1) Monday
