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( 1 ) A train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going ?
 1) 10 sec.
 2) 12 sec.
 3) 14 sec.
 4) 16 sec.

Show Answer Report Discussion in forumAnswer : 2) 12 sec.
Solution : Speed of train relative to man = (59 + 7) km/hr = 66 km/hr.
= 66 * 5/18 m/sec
= 55/3 m/sec.
Time taken to pass the man = 220 * 3/55 sec = 12 sec.
discussion
Answer : 2) 12 sec.



( 2 ) Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
 1) 10
 2) 12
 3) 15
 4) 20

Show Answer Report Discussion in forumAnswer : 2) 12
Solution : Speed of the first train = ( 120 /10) m/sec = 12 m/sec.
Speed of the second train = ( 120 /15) m/sec = 8 m/sec.
Relative speed = (12 + 8) = 20 m/sec.
Therefore Required time = [ (120 + 120) /20] sec = 12 sec.
discussion
Answer : 2) 12



( 3 ) Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is :
 1) 1:03
 2) 3:02
 3) 3:04
 4) 2:03

Show Answer Report Discussion in forumAnswer : 2) 3:02
Solution : Let the Speed of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x meters, and length of the second train = 17y meters.
(27x + 17y)/(x + y) = 23
=> 27x + 17y = 23x+ 23y
=> 4x = 6y
=> x/y = 3/2.
discussion
Answer : 2) 3:02



( 4 ) A train covers the distance 50 m between two cities in 4 hours arriving 2 hours late. What rate would permit the train to arrive on schedule:
 1) 25 km/hr
 2) 30 km/hr
 3) 28 km/hr
 4) 26 km/hr

Show Answer Report Discussion in forumAnswer : 1) 25 km/hr
Solution : Speed = Distance/Time
Distance = 50 km
Time taken = 4
But train is late by 2 hours
So, the time taken should have been 4  2
So, Speed required to be on time = 50/(4  2) = 50/2 = 25 km/hr
discussion
Answer : 1) 25 km/hr



( 5 ) A train moves with a speed of 108 kmph.Its speed in metres per second is ?
 1) 10.8 m/sec
 2) 18m/sec
 3) 30m/sec
 4) 38.8m/sec

Show Answer Report Discussion in forumAnswer : 3) 30m/sec
Solution : Speed = 108 Kmph
= (108 * 5/18)m/sec = 30 m/sec.
discussion
Answer : 3) 30m/sec



( 6 ) A 360 metre long train crosses a platform in 40 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
 1) 320 m
 2) 440 m
 3) 650 m
 4) 550 m

Show Answer Report Discussion in forumAnswer : 2) 440 m
Solution : Speed = Distance/time = 360/18 = 20 m/sec
Let the length of the platform be x meter
Then Distance = Speed * Time
x + 360 = 20*40
=> x + 360 = 800
=> x = 800  360
=> x = 440 meter
discussion
Answer : 2) 440 m



( 7 ) How long does a train 110 metres long running at the speed of 72 km / hr take to cross a bridge 132 metres in length ??
 1) 9.8 sec
 2) 12.1 sec
 3) 14.3 sec
 4) 12.42 sec

Show Answer Report Discussion in forumAnswer : 2) 12.1 sec
Solution : Speed = (72 * 5/18 )m/sec = 20 m/ sec
Total Distance covered = (110 + 132) m = 242 m
Required time = (242 / 60) sec = 12.1 sec
discussion
Answer : 2) 12.1 sec



( 8 ) Two stations P and Q are 110 km apart on a straight line. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?
 1) 9 a.m
 2) 10 a.m.
 3) 10.30 a.m.
 4) 11 a.m

Show Answer Report Discussion in forumAnswer : 2) 10 a.m.
Solution : Suppose they meet x hours after 7 a.m.
Distance covered by P in x hours = 20x km.
Distance covered by Q in (x  1) hours = 25(x  1) km.
Therefore 20x + 25(x  1) = 110
=> 45x = 135
=> x = 3.
So, they meet at 10 a.m.
discussion
Answer : 2) 10 a.m.



( 9 ) A train 132 m long passes a telegraph pole in 6 seconds. Find the speed of the train?
 1) 70 km/hr
 2) 72 km/hr
 3) 79.2 km/hr
 4) 80 km/hr

Show Answer Report Discussion in forumAnswer : 3) 79.2 km/hr
Solution : Speed = (132 / 6) m/sec
= (22 * 18 /5)km/hr
= 79.2 km/hr
discussion
Answer : 3) 79.2 km/hr



( 10 ) A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the Length of the other train ?
 1) 230 m
 2) 240 m
 3) 260 m
 4) 320 m

Show Answer Report Discussion in forumAnswer : 1) 230 m
Solution : Relative Speed = (120 + 80)km/hr
= (200 * 5/18)m/sec
= (500 / 9)m/sec
Let the length of the other train be x metres
Then, x + 270 / 9
x + 270 = 500
x = 230.
discussion
Answer : 1) 230 m
