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C Language
C++ language
JAVA
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( 1 ) What will be the output of the following program?
#include< stdio.h>
Void f(static int*, extern int);
Static int b = 12;
Int main()
{
Static int a[5];
Register int I;
For(I = 0; I < 2; I ++);
A[i++] = 2 * i++;
F(a, b);
For(I = 0; I < 2; I ++)
Printf("%d", b++);
Return 0;
}
Void f (static int *x, extern int y)
{
Register int I;
For(I = 0; I < 2; I ++)
*(++x +1) + = 2;
Y + = 2;
} - 1) 0 0
- 2) 0 6
- 3) 0 12
- 4) 12 12
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( 2 ) What will be the output of the following code?
static int I = 5;
main()
{
int sum = 0
do
{
sum + = (1/i);
}while(0 < I - -);
printf("sum of the series is %d", sum);
} - 1) It will print the sum of the series 1/5+1/4+. . .+1/1.
- 2) It will produce a compilation error.
- 3) It will produce a run time error.
- 4) None of these
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Show Answer Report Discussion in forumAnswer : 3) It will produce a run time error.
Solution :
discussion
Answer : 3) It will produce a run time error.
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( 3 ) Regarding the scope of the variables identify the incorrect statement:
- 1) Automatic variables are automatically initialized to 0
- 2) Static variables are automatically initialized to 0
- 3) The address of a register variable is not accessible
- 4) Static variables cannot be initialized with any expression
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Show Answer Report Discussion in forumAnswer : 1) Automatic variables are automatically initialized to 0
Solution : By default Automatic variables are initialized to Garbage value.
discussion
Answer : 1) Automatic variables are automatically initialized to 0
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( 4 ) calloc() returns a storage that is initialized to.
- 1) Zero
- 2) Null
- 3) Nothing
- 4) One
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( 5 ) What is the output of the following program?
#include
static float x=1.2;
void main()
{
printf("%f ",x);
printf("%d ",y);
my_func();
}
static int y=5;
int my_func()
{
printf("%f ",x);
printf("%d ",y);
return 0;
} - 1) 1.200000 5 1.200000 5
- 2) 1.200000 0 1.200000 5
- 3) 1.200000 0 1.200000 0
- 4) Compiler Error
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Show Answer Report Discussion in forumAnswer : 4) Compiler Error
Solution :
discussion
Answer : 4) Compiler Error
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( 6 ) What is the output of the following program
#include
int main()
{
register int a=10;
int *p;
p=&a;
printf("%u",p);
return 0;
} - 1) Compiler Error
- 2) 10
- 3) adress of a
- 4) None of these
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Show Answer Report Discussion in forumAnswer : 1) Compiler Error
Solution : We cannot dereference register variable since it has not any memory address
discussion
Answer : 1) Compiler Error
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( 7 ) Output?
#include
int a, b, c = 0;
void prtFun (void);
int main ()
{
static int a = 1; /* line 1 */
prtFun();
a += 1;
prtFun();
printf ( "\n %d %d " , a, b) ;
}
void prtFun (void)
{
static int a = 2; /* line 2 */
int b = 1;
a += ++b;
printf (" \n %d %d " , a, b);
} - 1) 3 1
4 1
4 2 - 2) 4 2
6 1
6 1 - 3) 4 2
6 2
2 0 - 4) 3 1
5 2
5 2 -
Show Answer Report Discussion in forumAnswer : 3) 4 2
6 2
2 0
Solution :
discussion
Answer : 3) 4 2
6 2
2 0
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( 8 ) Memory allocation using malloc() is done in?
- 1) Static area
- 2) Stack area
- 3) Heap area
- 4) Both 2 & 3
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Show Answer Report Discussion in forumAnswer : 3) Heap area
Solution :
discussion
Answer : 3) Heap area
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( 9 ) Output of following program
#include
int fun(int n)
{
static int s = 0;
s = s + n;
return (s);
} int main() { int i = 10, x; while (i > 0) { x = fun(i); i--; } printf ("%d ", x); return 0; } - 1) 0
- 2) 100
- 3) 110
- 4) 55
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( 10 ) Where will the space be allocated for an automatic storage class variable?
- 1) In CPU register
- 2) In memory as well as in CPU register
- 3) In memory
- 4) On disk.
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Show Answer Report Discussion in forumAnswer : 3) In memory
Solution :
discussion
Answer : 3) In memory
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