• ( 1 ) How many numbers from 29 to 79 are exactly divisible by 11.

    • 1) 5
    • 2) 6
    • 3) 4
    • 4) 7
    • Discussion in forum
      Answer : 1) 5
      Solution : 29/11 = 2 and 79/11 = 7
      => 7 - 2 = 5 Numbers








      discussion


      Answer : 1) 5

    • ( 2 ) How many numbers from 10 to 50 are exactly divisible by 3.

    • 1) 13
    • 2) 12
    • 3) 14
    • 4) 11
    • Discussion in forum
      Answer : 2) 12
      Solution : 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45,48.
      13 Numbers.
      10/3 = 3 and 50/3 = 16
      => 16 - 3 = 13. Therefore 13 digits.








      discussion


      Answer : 2) 12

    • ( 3 ) In a question on division with zero remainder, a candidate took 12 as divisor instead of 21. The quotient obtained by him was 35. The correct quotient is:

    • 1) 26
    • 2) 25
    • 3) 0
    • 4) 20
    • Discussion in forum
      Answer : 4) 20
      Solution : Number = (35 * 12) = 420
      Correct quotient = 420/21 = 20








      discussion


      Answer : 4) 20

    • ( 4 ) What is the dividend. divisor 17, the quotient is 9 and the remainder is 5.

    • 1) 153
    • 2) 156
    • 3) 158
    • 4) NONE
    • Discussion in forum
      Answer : 3) 158
      Solution : D = d * Q + R
      D = 17 * 9 + 5
      D = 153 + 5
      D = 158








      discussion


      Answer : 3) 158

    • ( 5 ) On dividinng 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.

    • 1) 13
    • 2) 12
    • 3) 14
    • 4) 11
    • Discussion in forum
      Answer : 2) 12
      Solution : d = (D - R)/Q
      = (109 - 1)/9
      = 108/9 = 12








      discussion


      Answer : 2) 12

    • ( 6 ) The greatest number by which the product of three consecutive multiples of 3 is always

    • 1) 54
    • 2) 81
    • 3) 162
    • 4) 243
    • Discussion in forum
      Answer : 3) 162
      Solution : 3*6*9 = 162








      discussion


      Answer : 3) 162

    • ( 7 ) What least number must be subtracted from 427398 so that remaining number is divisible by 15

    • 1) 3
    • 2) 5
    • 3) 7
    • 4) 9
    • Discussion in forum
      Answer : 1) 3
      Solution : On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted








      discussion


      Answer : 1) 3

    • ( 8 ) A certain number when divided by 899 leaves the remainder 65. when the same number is divided by 31, the remainder is:

    • 1) 2
    • 2) 3
    • 3) 4
    • 4) 1
    • Discussion in forum
      Answer : 2) 3
      Solution : 899 is divided by 31
      ∴ required remainder = remainder by 65/31 = 3








      discussion


      Answer : 2) 3

    • ( 9 ) The unit digit in the product (122)173 is

    • 1) 2
    • 2) 4
    • 3) 6
    • 4) 8
    • Discussion in forum
      Answer : 1) 2
      Solution : Power of (122)173 is odd number
      ∴unit digit in the product of (122)173 = 2








      discussion


      Answer : 1) 2

    • ( 10 ) Two numbers, when divided by 17, leave remainders 13 and 11 respectively. If the sum of those two numbers is divided by 17, the remainder will be

    • 1) 13
    • 2) 11
    • 3) 7
    • 4) 4
    • Discussion in forum
      Answer : 3) 7
      Solution : Required remainder = remainder by (13 +11)/17 = 7








      discussion


      Answer : 3) 7





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